-16x^2+26x+125=0

Solution for -16x^2+26x+125=0 equation:

-16x^2+26x+125=0

a = -16; b = 26; c = +125;
Δ = b2-4ac
Δ = 262-4·(-16)·125
Δ = 8676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8676}=\sqrt{36*241}=\sqrt{36}*\sqrt{241}=6\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-6\sqrt{241}}{2*-16}=\frac{-26-6\sqrt{241}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+6\sqrt{241}}{2*-16}=\frac{-26+6\sqrt{241}}{-32}
$